Modern Physics Preparation Hub
Master Modern Physics with coaching-grade theory notes, verified video lectures, and 10 interactive MCQs with instant mistake analysis. Continue with 500+ adaptive questions inside the Exam Sprinter app.
What is Modern Physics?
Modern Physics covers the essential principles and concepts required for JEE Main.
π‘ Why Study Modern Physics?
Highly important, frequently tested in JEE Main.
| Parameter | Details / Relevance |
|---|---|
| Target Exam | JEE Main |
| Subject Category | Physics |
| Estimated Study Duration | 10 Hours |
| Expected Questions | 2 Questions |
| Difficulty Index | Medium |
| Interactive Solved MCQs | 10 Questions with AI Diagnostics |
| Adaptive App Practice | 500+ Questions & Real-Time AI Tutor |
β οΈ Common Pitfalls to Avoid
- Rushing through mathematical derivations without checking boundary conditions and signs.
- Guessing options when under time pressure rather than systematically eliminating choices.
- Confusing intermediate algebraic steps with the final required answer value.
Modern Physics Theory & Derivations
Access comprehensive classroom-grade derivations and NCERT micro-extracts for Modern Physics. Features step-by-step proofs and standard assumptions.
Important Formulas & Cheat Sheet
- $$E = hf = \frac{hc}{\lambda}$$
- $$\lambda = \frac{h}{mv}$$ (de Broglie)
- $$E_n = -\frac{13.6}{n^2}$$ eV
- $$N = N_0 e^{-\lambda t}$$
Modern Physics Interactive Practice
Solve these 10 standard exam-level questions. The system tracks your response time, detects rapid guessing via Cognitive Reading Thresholds, and outputs your post-session diagnosis.
During the propagation of electromagnetic waves in a medium :
Identify the logic operation carried out.
The reading of the ammeter for a silicon diode in the given circuit is :
If the kinetic energy of a free electron doubles, it's deBroglie wavelength changes by the factor
Given below are two statements : Statement I : Figure shows the variation of stopping potential with frequency for the two photosensitive materials and . The slope gives value of , where is Planck's constant, e is the charge of electron. Statement II : will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements, choose the most appropriate answer from the options given below.
The following diagram shows a Zener diode as a voltage regulator. The Zener diode is rated at and the desired current in load is 5 mA . The unregulated voltage source can supply upto 25 V . Considering the Zener diode can withstand four times of the load current, the value of resistor (shown in circuit) should be .
In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300 nm to 400 nm. The decrease in the stopping potential is close to: ( = 1240 nm eV)
In the hydrogen atom, the electron makes a transition from the higher orbit (i) to a lower orbit . The ratio of the radius of the orbits in given by . The wavelength of photon emitted due to this transition is nm. (Given Rydberg constant )
An electron from various excited states of hydrogen atom emit radiation to come to the ground state. Let , be the de Broglie wavelength of the electron in the nth state and the ground state respectively. Let be the wavelength of the emitted photon in the transition from the nth state to the ground state. For large n, (A, B are constants)
For a nucleus having mass number and atomic number A. The surface energy per nucleon . B. The Coulomb contribution to the binding energy C. The volume energy D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. ( and are constants) Choose the most appropriate answer from the options given below:
πΊοΈ Recommended Learning Sequence
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