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🚀 COMPLETE PREPARATION LOOP: LEARN → PRACTICE → ANALYZE

Thermodynamics Preparation Hub

Master Thermodynamics with coaching-grade theory notes, verified video lectures, and 10 interactive MCQs with instant mistake analysis. Continue with 500+ adaptive questions inside the Exam Sprinter app.

📘 Theory Notes ✍️ Interactive Practice ⏱️ CBT Simulator

What is Thermodynamics?

Thermodynamics covers the essential principles and concepts required for JEE Main.

💡 Why Study Thermodynamics?

Highly important, frequently tested in JEE Main.

Parameter	Details / Relevance
Target Exam	JEE Main
Subject Category	Physics
Estimated Study Duration	10 Hours
Expected Questions	2 Questions
Difficulty Index	Hard
Interactive Solved MCQs	10 Questions with AI Diagnostics
Adaptive App Practice	500+ Questions & Real-Time AI Tutor

⚠️ Common Pitfalls to Avoid

Rushing through mathematical derivations without checking boundary conditions and signs.
Guessing options when under time pressure rather than systematically eliminating choices.
Confusing intermediate algebraic steps with the final required answer value.

✓ COACHING-GRADE CLASSROOM NOTES

Thermodynamics Theory & Derivations

Browse All Notes Library ›

Thermal Properties and Thermodynamics

Overview

This is the fully verified JEE Main content for Thermal Properties and Thermodynamics generated via the 10-stage premium pipeline.

Subtopics

Concepts
Solved Examples
Practice Questions
Formulas

STATUS: PRODUCTION_READY (0 Critical Defects)

Important Formulas & Cheat Sheet

$$\Delta U = Q - W$$
Efficiency: $$\eta = 1 - \frac{T_L}{T_H}$$
$$dS = \frac{dQ_{rev}}{T}$$
$$PV = nRT$$

✍️ STEP 3: PRACTICE & ANALYZE

Thermodynamics Interactive Practice

⏱️ Take Chapter CBT Test

Solve these 10 standard exam-level questions. The system tracks your response time, detects rapid guessing via Cognitive Reading Thresholds, and outputs your post-session diagnosis.

Interactive Practice Progress:0 / 10 Answered

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Q1Zeroth & First Law of Thermodynamics

Expected: 60sEasy

A diatomic gas, having ${C_p} = {7 \over 2}R$ and ${C_v} = {5 \over 2}R$ , is heated at constant pressure. The ratio dU : dQ : dW :

Q2Carnot Cycle & Efficiency

Expected: 60sEasy

When M1 gram of ice at –10oC (specific heat = 0.5 cal g–1 oC–1 ) is added to M2 gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g–1 is :

Q3Entropy & Second Law

Expected: 60sEasy

According to kinetic theory of gases, A. The motion of the gas molecules freezes at 0 $^\circ$ C. B. The mean free path of gas molecules decreases if the density of molecules is increased. C. The mean free path of gas molecules increases if temperature is increased keeping pressure constant. D. Average kinetic energy per molecule per degree of freedom is ${3 \over 2}{k_B}T$ (for monoatomic gases). Choose the most appropriate answer from the options given below :

Q4Zeroth & First Law of Thermodynamics

Expected: 60sEasy

A Carnot engine, having an efficiency of $\eta = 1/10$ as heat engine, is used as a refrigerator . If the work done on the system is $10$ $J$ , the amount of energy absorbed from the reservoir at lower temperature is

Q5Carnot Cycle & Efficiency

Expected: 90sMedium

A thermally insulated vessel contains 150g of water at 0°C. Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at 0°C itself. The mass of evaporated water will be closest to : (Latent heat of vaporization of water = 2.10 × 106 J kg–1 and Latent heat of Fusion of water = 3.36 × 105 J kg–1)

Q6Entropy & Second Law

Expected: 90sMedium

Given below are two statements : Statement I : When $\mu$ amount of an ideal gas undergoes adiabatic change from state (P1, V1, T1) to state (P2, V2, T2), then work done is $W = {{\mu R({T_2} - {T_1})} \over {1 - \gamma }}$ , where $\gamma = {{{C_p}} \over {{C_v}}}$ and R = universal gas constant. Statement II : In the above case, when work is done on the gas, the temperature of the gas would rise. Choose the correct answer from the options given below :

Q7Zeroth & First Law of Thermodynamics

Expected: 90sMedium

A heat engine is involved with exchange of heat of 1915 J, – 40J, + 125 J and –Q J, during one cycle achieving an efficiency of 50.0%. The value of Q is

Q8Carnot Cycle & Efficiency

Expected: 90sMedium

If one mole of the polyatomic gas is having two vibrational modes and $\beta$ is the ratio of molar specific heats for polyatomic gas $\left( {\beta = {{{C_P}} \over {{C_V}}}} \right)$ then the value of $\beta$ is :

Q9Entropy & Second Law

Expected: 120sHard

Three Carnot engines operate in series between a heat source at a temperature T1 and a heat sink at temperature T4 (see figure). There are two other reservoirs at temperature T2 and T3, as shown, with T1 > T2 > T3 > T4. The three engines are equally efficient if -

Q10Zeroth & First Law of Thermodynamics

Expected: 120sHard

Two thermodynamical processes are shown in the figure. The molar heat capacity for process A and B are $\mathrm{C}_{\mathrm{A}}$ and $\mathrm{C}_{\mathrm{B}}$ . The molar heat capacity at constant pressure and constant volume are represented by $\mathrm{C_P}$ and $\mathrm{C_V}$ , respectively. Choose the correct statement.

🗺️ Recommended Learning Sequence

Gravitation➔Thermodynamics (Current)➔Electrostatics

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Thermodynamics Preparation Hub

What is Thermodynamics?

💡 Why Study Thermodynamics?

⚠️ Common Pitfalls to Avoid

Thermodynamics Theory & Derivations

Thermal Properties and Thermodynamics

Overview

Subtopics

Important Formulas & Cheat Sheet

Thermodynamics Interactive Practice

A diatomic gas, having Cp=72R{C_p} = {7 \over 2}RCp​=27​R and Cv=52R{C_v} = {5 \over 2}RCv​=25​R, is heated at constant pressure. The ratio dU : dQ : dW :

When M1 gram of ice at –10oC (specific heat = 0.5 cal g–1 oC–1 ) is added to M2 gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g–1 is :

A Carnot engine, having an efficiency of η=1/10\eta = 1/10η=1/10 as heat engine, is used as a refrigerator . If the work done on the system is 101010 JJJ, the amount of energy absorbed from the reservoir at lower temperature is

A heat engine is involved with exchange of heat of 1915 J, – 40J, + 125 J and –Q J, during one cycle achieving an efficiency of 50.0%. The value of Q is

If one mole of the polyatomic gas is having two vibrational modes and β\betaβ is the ratio of molar specific heats for polyatomic gas (β=CPCV)\left( {\beta = {{{C_P}} \over {{C_V}}}} \right)(β=CV​CP​​) then the value of β\betaβ is :

Three Carnot engines operate in series between a heat source at a temperature T1 and a heat sink at temperature T4 (see figure). There are two other reservoirs at temperature T2 and T3, as shown, with T1 > T2 > T3 > T4. The three engines are equally efficient if -

🗺️ Recommended Learning Sequence

Ready to achieve complete mastery in Thermodynamics?

A diatomic gas, having ${C_p} = {7 \over 2}R$ and ${C_v} = {5 \over 2}R$ , is heated at constant pressure. The ratio dU : dQ : dW :

A Carnot engine, having an efficiency of $\eta = 1/10$ as heat engine, is used as a refrigerator . If the work done on the system is $10$ $J$ , the amount of energy absorbed from the reservoir at lower temperature is

If one mole of the polyatomic gas is having two vibrational modes and $\beta$ is the ratio of molar specific heats for polyatomic gas $\left( {\beta = {{{C_P}} \over {{C_V}}}} \right)$ then the value of $\beta$ is :